-10n^2-20n=10

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Solution for -10n^2-20n=10 equation: 



-10n^2-20n=10

We move all terms to the left:

-10n^2-20n-(10)=0

a = -10; b = -20; c = -10;
Δ = b2-4ac
Δ = -202-4·(-10)·(-10)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{20}{-20}=-1$

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